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The Most Wanted Letter？
#function 
def getMostLetter(password):
    pass_lower = password.lower()
    lst = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
    princ = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
    for i in pass_lower:
        cnt = 0
        for j in princ:
            if i == j:
                lst[cnt] = lst[cnt] + 1
            cnt = cnt + 1
    lstmax = max(lst)
    index_letter = lst.index(lstmax)
    return princ[index_letter]
    
  other solves:
  
  
  import string

def checkio(text):
    """
    We iterate through latyn alphabet and count each letter in the text.
    Then 'max' selects the most frequent letter.
    For the case when we have several equal letter,
    'max' selects the first from they.
    """
    text = text.lower()
    return max(string.ascii_lowercase, key=text.count)