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ts.c
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/* sudoku.c
* Sudoku solver, representing cell candidates as bitvectors
*/
#include <stdio.h>
#include <stdint.h>
#include <stdlib.h>
#include <string.h>
#include "util.h"
static uint16_t cells[HOUSE_SZ][HOUSE_SZ]; // Candidates
static uint16_t solved[HOUSE_SZ][HOUSE_SZ]; // Solutions
// Get block number (0->9 reading left-right top-bottom) from i,j coordinates
// Block index is i rounded down to nearest multiple of cell size + j divided by cell size
static inline int blk_index(int i, int j) {
return (i / BLK_WIDTH) * BLK_WIDTH + j / BLK_WIDTH;
}
// Get i,j coordinates of top left cell in a block from its index
static void blk_coords(int n, int *i, int *j) {
*i = (n / BLK_WIDTH) * BLK_WIDTH;
*j = (n % BLK_WIDTH) * BLK_WIDTH;
}
// Check if board is solved - each row/column/block is solved
// if the xor of all cells is 0x1ff (1 bit set)
int is_solved(uint16_t row[HOUSE_SZ], uint16_t col[HOUSE_SZ], uint16_t blk[HOUSE_SZ]) {
for (int i = 0; i < HOUSE_SZ; i++) {
for (int j = 0; j < HOUSE_SZ; j++) {
uint16_t c = solved[i][j];
if (c) {
row[i] |= c;
col[j] |= c;
blk[blk_index(i, j)] |= c;
}
}
}
uint16_t target = (1 << HOUSE_SZ) - 1;
for (int i = 0; i < HOUSE_SZ; i++) {
if ((row[i] & col[i] & blk[i]) ^ target) {
return 0;
}
}
return 1;
}
// Eliminate as candidate value of solved cell & propagate any other
// solved cells process creates
void remove_candidate(int i, int j) {
uint16_t elim = ~cells[i][j];
solved[i][j] = cells[i][j];
cells[i][j] = 0;
for (int x = 0; x < HOUSE_SZ; x++) {
if (cells[i][x]) {
cells[i][x] &= elim;
if (!(cells[i][x] & (cells[i][x] - 1))) {
remove_candidate(i, x);
}
}
}
for (int y = 0; y < HOUSE_SZ; y++) {
if (cells[y][j]) {
cells[y][j] &= elim;
if (!(cells[y][j] & (cells[y][j] - 1))) {
remove_candidate(y, j);
}
}
}
int z1, z2;
blk_coords(blk_index(i, j), &z1, &z2);
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
if (cells[a][b]) {
cells[a][b] &= elim;
if (!(cells[a][b] & (cells[a][b] - 1))) {
remove_candidate(a, b);
}
}
}
}
}
// Hidden singles strategy
static void singles() {
// Look for hidden singles in each row
for (int i = 0; i < HOUSE_SZ; i++) {
int opts_count[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int j = 0; j < HOUSE_SZ; j++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][j] >> k) & 1;
}
}
uint16_t singles = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 1) {
singles |= 1 << k;
}
}
// Find cells that have one of the hidden singles
for (int j = 0; j < HOUSE_SZ; j++) {
if (cells[i][j] & singles) {
cells[i][j] &= singles;
remove_candidate(i, j);
// Recalculate opts_count & singles
// as they may have changed in propagation
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int l = 0; l < HOUSE_SZ; l++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][l] >> k) & 1;
}
}
uint16_t singles = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 1) {
singles |= 1 << k;
}
}
j = 0; // Go back to beginning
}
}
}
// Column
for (int j = 0; j < HOUSE_SZ; j++) {
// Count number of cells that can hold each number
int opts_count[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int i = 0; i < HOUSE_SZ; i++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][j] >> k) & 1;
}
}
// Create bitvector of numbers with only one possibility
uint16_t singles = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 1) {
singles |= 1 << k;
}
}
// Find cells that have one of the hidden singles
for (int i = 0; i < HOUSE_SZ; i++) {
if (cells[i][j] & singles) {
cells[i][j] &= singles;
remove_candidate(i, j);
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int l = 0; l < HOUSE_SZ; l++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[l][j] >> k) & 1;
}
}
// Create bitvector of numbers with only one possibility
uint16_t singles = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 1) {
singles |= 1 << k;
}
}
i = 0;
}
}
}
// Block
for (int z = 0; z < HOUSE_SZ; z++) {
int opts_count[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
int z1, z2;
blk_coords(z, &z1, &z2);
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[a][b] >> k) & 1;
}
}
}
uint16_t singles = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 1) {
singles |= 1 << k;
}
}
// Find cells that have one of the hidden singles
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
if (cells[a][b] & singles) {
cells[a][b] &= singles;
remove_candidate(a, b);
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int a2 = z1; a2 < z1 + BLK_WIDTH; a2++) {
for (int b2 = z2; b2 < z2 + BLK_WIDTH; b2++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[a2][b2] >> k) & 1;
}
}
}
uint16_t singles = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 1) {
singles |= 1 << k;
}
}
a = z1;
b = z2;
}
}
}
}
}
// Use naked pairs strategy to eliminate further options
// Naked pair: two cells in same house that have only two identical possibilities
static void naked_pairs() {
for (int i = 0; i < HOUSE_SZ; i++) {
for (int j = 0; j < HOUSE_SZ; j++) {
if (bit_count(cells[i][j]) == 2) {
// Check for pairs in remainder of row, eliminating possibiliities
// from row if so
for (int k = j + 1; k < HOUSE_SZ; k++) {
// same pair
if (cells[i][j] == cells[i][k]) {
for (int x = 0; x < HOUSE_SZ; x++) {
if (cells[i][x] && x != j && x != k) {
cells[i][x] &= ~cells[i][j];
if(!(cells[i][x] & (cells[i][x] - 1))) {
remove_candidate(i, x);
}
}
}
break; // there won't (shouldn't) be another pair
}
}
// Column
for (int k = i + 1; k < HOUSE_SZ; k++) {
if (cells[i][j] == cells[k][j]) {
for (int y = 0; y < HOUSE_SZ; y++) {
if (cells[y][j] && y != i && y != k) {
cells[y][j] &= ~cells[i][j];
if (!(cells[y][j] & (cells[y][j] - 1))) {
remove_candidate(y, j);
}
}
}
break;
}
}
// Block
int z1, z2;
blk_coords(blk_index(i, j), &z1, &z2);
for (int a = i; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
if (a == i && b <= j)
continue;
if (cells[i][j] == cells[a][b]) {
for (int k = z1; k < z1 + BLK_WIDTH; k++) {
for (int l = z2; l < z2 + BLK_WIDTH; l++) {
if (cells[k][l] && cells[i][j] != cells[k][l]) {
cells[k][l] &= ~cells[i][j];
if (!(cells[k][l] & (cells[k][l] - 1))) {
remove_candidate(k, l);
}
}
}
}
break;
}
}
}
}
}
}
}
// Apply hidden pairs strategy: look for pairs of cells in each house
// that are the only ones that can have 2 options
static void hidden_pairs() {
int opts_count[HOUSE_SZ];
uint16_t pairs;
// Look for hidden pairs in each row
for (int i = 0; i < HOUSE_SZ; i++) {
// Count number of cells that can hold each number
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int j = 0; j < HOUSE_SZ; j++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][j] >> k) & 1;
}
}
// Make bitvector of numbers that can only go in two cells
pairs = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 2) {
pairs |= 1 << k;
}
}
if(bit_count(pairs) >= 2) {
// Find pairs of cells that share two of the possibilities
for (int j = 0; j < HOUSE_SZ; j++) {
for (int x = j + 1; x < HOUSE_SZ; x++) {
uint16_t inter = cells[i][j] & cells[i][x] & pairs;
if (bit_count(inter) == 2) {
cells[i][j] = inter;
cells[i][x] = inter;
pairs &= ~inter;
}
}
}
}
}
// Column
for (int j = 0; j < HOUSE_SZ; j++) {
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int i = 0; i < HOUSE_SZ; i++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][j] >> k) & 1;
}
}
pairs = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 2) {
pairs |= 1 << k;
}
}
if(bit_count(pairs) >= 2) {
for (int i = 0; i < HOUSE_SZ; i++) {
for (int y = i + 1; y < HOUSE_SZ; y++) {
uint16_t inter = cells[i][j] & cells[y][j] & pairs;
if (bit_count(inter) == 2) {
cells[i][j] = inter;
cells[y][j] = inter;
pairs &= ~inter;
}
}
}
}
}
// Block
for (int z = 0; z < HOUSE_SZ; z++) {
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
int z1, z2;
blk_coords(z, &z1, &z2);
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[a][b] >> k) & 1;
}
}
}
pairs = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 2) {
pairs |= 1 << k;
}
}
if (bit_count(pairs) >= 2) {
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
for (int x = a; x < z1 + BLK_WIDTH; x++) {
for (int y = z2; y < z2 + BLK_WIDTH; y++) {
if (x > a || (x == a && y > b)) {
uint16_t inter = cells[a][b] & cells[x][y] & pairs;
if (bit_count(inter) == 2) {
cells[a][b] = inter;
cells[x][y] = inter;
pairs &= ~cells[a][b];
}
}
}
}
}
}
}
}
}
// Claiming pairs strategy: Find pairs of cells in the same row/column
// that are in the same block, and eliminate that candidate from the block
static void claiming_pairs() {
// Look for claiming pairs in each row
for (int i = 0; i < HOUSE_SZ; i++) {
// Count number of cells that can hold each number
int opts_count[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int j = 0; j < HOUSE_SZ; j++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][j] >> k) & 1;
}
}
// Make a bitvector of numbers that can only go in two cells
uint16_t pairs = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 2) {
pairs |= 1 << k;
}
}
if (bit_count(pairs) >= 1) {
// Find the pairs of cells with these numbers
for (int j = 0; j < HOUSE_SZ; j++) {
uint16_t inter = cells[i][j] & pairs;
if (inter) {
// Check remainder of intersection with block for other pair
int z1, z2;
blk_coords(blk_index(i, j), &z1, &z2);
for (int k = j + 1; k < z2 + BLK_WIDTH; k++) {
uint16_t pair = inter & cells[i][k];
if (pair) {
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
if (cells[a][b] && !(a == i && b == j) && !(a == i && b == k)) {
cells[a][b] &= ~pair;
if (!(cells[a][b] & (cells[a][b] - 1))) {
remove_candidate(a, b);
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int j2 = 0; j2 < HOUSE_SZ; j2++) {
for (int k2 = 0; k2 < HOUSE_SZ; k2++) {
opts_count[k2] += (cells[i][j2] >> k2) & 1;
}
}
// Make a bitvector of numbers that can only go in two cells
uint16_t pairs = 0;
for (int k2 = 0; k2 < HOUSE_SZ; k2++) {
if (opts_count[k] == 2) {
pairs |= 1 << k2;
}
}
}
}
}
}
}
}
}
}
}
}
// Columns
for (int j = 0; j < HOUSE_SZ; j++) {
int opts_count[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int i = 0; i < HOUSE_SZ; i++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][j] >> k) & 1;
}
}
uint16_t pairs = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 2) {
pairs |= 1 << k;
}
}
if (bit_count(pairs) >= 1) {
for (int i = 0; i < HOUSE_SZ; i++) {
uint16_t inter = cells[i][j] & pairs;
if (inter) {
int z1, z2;
blk_coords(blk_index(i, j), &z1, &z2);
for (int k = i + 1; k < z1 + BLK_WIDTH; k++) {
uint16_t pair = inter & cells[k][j];
if (pair) {
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
if (cells[a][b] && !(a == i && b == j) && !(a == k && b == j)) {
cells[a][b] &= ~pair;
if (!(cells[a][b] & (cells[a][b] - 1))) {
remove_candidate(a, b);
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int i2 = 0; i2 < HOUSE_SZ; i2++) {
for (int k2 = 0; k2 < HOUSE_SZ; k2++) {
opts_count[k2] += (cells[i2][j] >> k2) & 1;
}
}
uint16_t pairs = 0;
for (int k2 = 0; k2 < HOUSE_SZ; k2++) {
if (opts_count[k2] == 2) {
pairs |= 1 << k2;
}
}
}
}
}
}
}
}
}
}
}
}
}
// Pointing pairs strategy: Within a sqaure, find pairs of cells in the same
// row/column that are the only two that can have a number, eliminate this
// option from the row/column
static void pointing_pairs() {
// Look for pointing pairs in each block
for (int z = 0; z < HOUSE_SZ; z++) {
// Count number of cells that can hold each number
int opts_count[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
int z1, z2;
blk_coords(z, &z1, &z2);
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[a][b] >> k) & 1;
}
}
}
// Make bitvector of numbers that can only go in two cells
uint16_t pairs = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 2) {
pairs |= 1 << k;
}
}
if (bit_count(pairs) > 0) {
// Find the pairs of cells with these numbers
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
// If cell contains a pair, check the row/column for the other
uint16_t inter = cells[a][b] & pairs;
if (inter) {
// Column
for (int y = a + 1; inter && y < z1 + BLK_WIDTH; y++) {
uint16_t pair = inter & cells[y][b];
if (pair) {
for (int k = 0; k < HOUSE_SZ; k++) {
if (cells[k][b] && k != y && k != a) {
cells[k][b] &= ~pair;
if (!(cells[k][b] & (cells[k][b] - 1))) {
remove_candidate(k, b);
}
}
}
inter &= ~pair; // Pair is found
}
}
// Row
for (int x = b + 1; inter && x < z2 + BLK_WIDTH; x++) {
uint16_t pair = inter & cells[a][x];
if (pair) {
for (int k = 0; k < HOUSE_SZ; k++) {
if (cells[a][k] && k != x && k != b) {
cells[a][k] &= ~pair;
if (!(cells[a][k] & (cells[a][k] - 1))) {
remove_candidate(a, k);
}
}
}
inter &= ~pair; // Pair is found
}
}
}
}
}
}
}
}
// Pointing tuples strategy: same as pointing pairs, but is agnostic of
// group size
static void pointing_tuples() {
// Look for pointing tuples in each block
for (int z = 0; z < HOUSE_SZ; z++) {
int z1, z2;
blk_coords(z, &z1, &z2);
uint16_t rows[BLK_WIDTH];
uint16_t cols[BLK_WIDTH];
for (int i = 0; i < BLK_WIDTH; i++) {
rows[i] = 0;
cols[i] = 0;
}
for (int a = 0; a < BLK_WIDTH; a++) {
for (int b = 0; b < BLK_WIDTH; b++) {
rows[a] |= cells[z1 + a][z2 + b];
cols[b] |= cells[z1 + a][z2 + b];
}
}
// Columns
for (int i = 0; i < BLK_WIDTH; i++) {
for (int j = i + 1; j < BLK_WIDTH; j++) {
uint16_t inter = rows[i] & rows[j];
if (inter) {
for (uint16_t vec = 1; vec < 1 << HOUSE_SZ; vec <<= 1) {
if (vec & inter) {
int count = 0;
int col = 0;
for (int k = 0; k < BLK_WIDTH; k++) {
if (vec & cols[k]) {
vec &= cols[k];
col = k;
count++;
}
}
if (count == 1) {
for (int y = 0; y < HOUSE_SZ; y++) {
if ((y < z1 || y >= z1 + BLK_WIDTH) && cells[y][z2 + col]) {
cells[y][z2 + col] &= ~vec;
if (!(cells[y][z2 + col] & (cells[y][z2 + col] - 1))) {
remove_candidate(y, z2 + col);
}
}
}
}
}
}
}
}
}
// Rows
for (int j = 0; j < BLK_WIDTH; j++) {
for (int i = j + 1; i < BLK_WIDTH; i++) {
uint16_t inter = cols[i] & cols[j];
if (inter) {
for (uint16_t vec = 1; vec < 1 << HOUSE_SZ; vec <<= 1) {
if (vec & inter) {
int count = 0;
int row = 0;
for (int k = 0; k < BLK_WIDTH; k++) {
if (vec & rows[k]) {
vec &= rows[k];
row = k;
count++;
}
}
if (count == 1) {
for (int x = 0; x < HOUSE_SZ; x++) {
if ((x < z2 || x >= z2 + BLK_WIDTH) && cells[z1 + row][x]) {
cells[z1 + row][x] &= ~vec;
if (!(cells[z1 + row][x] & (cells[z1 + row][x] - 1))) {
remove_candidate(z1 + row, x);
}
}
}
}
}
}
}
}
}
}
}
static void hidden_triplets() {
int opts_count[HOUSE_SZ];
uint16_t triples;
// Look for hidden triplets in each row
for (int i = 0; i < HOUSE_SZ; i++) {
// Count number of cells that can hold each number
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int j = 0; j < HOUSE_SZ; j++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][j] >> k) & 1;
}
}
// Make bitvector of numbers that can only go in three cells
triples = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 3) {
triples |= 1 << k;
}
}
if(bit_count(triples) >= 3) {
// Find triples of cells that share three of the possibilities
for (int j = 0; j < HOUSE_SZ; j++) {
for (int jj = j + 1; jj < HOUSE_SZ; jj++) {
for (int jjj = jj + 1; jjj < HOUSE_SZ; jjj++) {
uint16_t inter = cells[i][j] & cells[i][jj] & cells[i][jjj] & triples;
if (bit_count(inter) == 3) {
cells[i][j] = inter;
cells[i][jj] = inter;
cells[i][jjj] = inter;
triples &= ~inter;
}
}
}
}
}
}
// Column
for (int j = 0; j < HOUSE_SZ; j++) {
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int i = 0; i < HOUSE_SZ; i++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][j] >> k) & 1;
}
}
triples = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 3) {
triples |= 1 << k;
}
}
if(bit_count(triples) >= 3) {
for (int i = 0; i < HOUSE_SZ; i++) {
for (int ii = i + 1; ii < HOUSE_SZ; ii++) {
for (int iii = ii + 1; iii < HOUSE_SZ; iii++) {
uint16_t inter = cells[i][j] & cells[ii][j] & cells[iii][j] & triples;
if (bit_count(inter) == 3) {
cells[i][j] = inter;
cells[ii][j] = inter;
cells[iii][j] = inter;
triples &= ~inter;
}
}
}
}
}
}
// Block
for (int z = 0; z < HOUSE_SZ; z++) {
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
int z1, z2;
blk_coords(z, &z1, &z2);
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[a][b] >> k) & 1;
}
}
}
triples = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 3) {
triples |= 1 << k;
}
}
if (bit_count(triples) >= 3) {
for (int a = z1; a < z1 + BLK_WIDTH; a++) {
for (int b = z2; b < z2 + BLK_WIDTH; b++) {
for (int aa = a; aa < z1 + BLK_WIDTH; aa++) {
for (int bb = z2; bb < z2 + BLK_WIDTH; bb++) {
if (aa > a || (aa == a && bb > b)) {
for (int aaa = aa; aaa < z1 + BLK_WIDTH; aaa++) {
for (int bbb = z2; bbb < z2 + BLK_WIDTH; bbb++) {
if (aaa > aa || (aaa == aa && bbb > bb)) {
uint16_t inter = cells[a][b] & cells[aa][bb] & cells[aaa][bbb] & triples;
if (bit_count(inter) == 3) {
cells[a][b] = inter;
cells[aa][bb] = inter;
cells[aaa][bbb] = inter;
triples &= ~inter;
}
}
}
}
}
}
}
}
}
}
}
}
// X-Wing strategy: An x-wing pattern is formed by two houses that have the same
// candidate pair in the same rows/columns. Eliminate candidate from rows/columns.
static void x_wing() {
// Row
// Build pair vectors for each row
// Bit is set in vector if that number appears exactly twice in row
uint16_t row_pairs[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
row_pairs[x] = 0;
}
for (int i = 0; i < HOUSE_SZ; i++) {
// Count number of cells that can hold each number
int opts_count[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int j = 0; j < HOUSE_SZ; j++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][j] >> k) & 1;
}
}
// Make bitvector of numbers that can only go in two cells
for (int k = 0; k < HOUSE_SZ; k++) {
if (opts_count[k] == 2) {
row_pairs[i] |= 1 << k;
}
}
}
// Identify x-wings in rows
for (int i = 0; i < HOUSE_SZ; i++) {
for (int j = i + 1; j < HOUSE_SZ; j++) {
uint16_t inter = row_pairs[i] & row_pairs[j];
for (int n = 0; (inter >> n) != 0; n++) {
if (!(inter & (1 << n)))
continue;
// Find columns of pair in row i
int col1 = 0, col2 = 0; // There should only be two - they are pairs
int found = 0;
for (int k = 0; k < HOUSE_SZ; k++) {
if (cells[i][k] & (1 << n)) {
if (!found) {
found = 1;
col1 = k;
} else {
col2 = k;
}
}
}
// Do columns match in row j? If so, eliminate from columns
if ((cells[j][col1] & (1 << n)) && (cells[j][col2] & (1 << n))) {
for (int k = 0; k < HOUSE_SZ; k++) {
if (k != i && k != j) {
cells[k][col1] &= ~(1 << n);
if (cells[k][col1] && !(cells[k][col1] & (cells[k][col1] - 1))) {
remove_candidate(k, col1);
for (int x = 0; x < HOUSE_SZ; x++) {
row_pairs[x] = 0;
}
for (int i2 = 0; i2 < HOUSE_SZ; i2++) {
int opts_count[HOUSE_SZ];
for (int x2 = 0; x2 < HOUSE_SZ; x2++) {
opts_count[x2] = 0;
}
for (int j2 = 0; j2 < HOUSE_SZ; j2++) {
for (int k2 = 0; k2 < HOUSE_SZ; k2++) {
opts_count[k2] += (cells[i2][j2] >> k2) & 1;
}
}
for (int k2 = 0; k2 < HOUSE_SZ; k2++) {
if (opts_count[k2] == 2) {
row_pairs[i2] |= 1 << k2;
}
}
}
}
cells[k][col2] &= ~(1 << n);
if (cells[k][col2] && !(cells[k][col2] & (cells[k][col2] - 1))) {
remove_candidate(k, col2);
for (int x = 0; x < HOUSE_SZ; x++) {
row_pairs[x] = 0;
}
for (int i2 = 0; i2 < HOUSE_SZ; i2++) {
int opts_count[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int j2 = 0; j2 < HOUSE_SZ; j2++) {
for (int k2 = 0; k2 < HOUSE_SZ; k2++) {
opts_count[k2] += (cells[i2][j2] >> k2) & 1;
}
}
for (int k2 = 0; k2 < HOUSE_SZ; k2++) {
if (opts_count[k2] == 2) {
row_pairs[i2] |= 1 << k2;
}
}
}
}
}
}
}
}
}
}
// Column
// Build pair vectors for each column
uint16_t col_pairs[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
col_pairs[x] = 0;
}
for (int j = 0; j < HOUSE_SZ; j++) {
// Count number of cells that can hold each number
int opts_count[HOUSE_SZ];
for (int x = 0; x < HOUSE_SZ; x++) {
opts_count[x] = 0;
}
for (int i = 0; i < HOUSE_SZ; i++) {
for (int k = 0; k < HOUSE_SZ; k++) {
opts_count[k] += (cells[i][j] >> k) & 1;