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1685-sumOfAbsoluteDifferences.ts
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1685-sumOfAbsoluteDifferences.ts
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// ---------------- LEETCODE TASK DESCRIPTION ----------------- //
// ----------- 1685 - SUM OF ABSOLUTE DIFFERENCES ------------- //
/* You are given an integer array nums sorted in non-decreasing order.
Build and return an integer array result with the same length as nums such that result[i] is equal to the summation of absolute differences between nums[i] and all the other elements in the array.
In other words, result[i] is equal to sum(|nums[i]-nums[j]|) where 0 <= j < nums.length and j != i (0-indexed).
Example 1:
Input: nums = [2,3,5]
Output: [4,3,5]
Explanation: Assuming the arrays are 0-indexed, then
result[0] = |2-2| + |2-3| + |2-5| = 0 + 1 + 3 = 4,
result[1] = |3-2| + |3-3| + |3-5| = 1 + 0 + 2 = 3,
result[2] = |5-2| + |5-3| + |5-5| = 3 + 2 + 0 = 5.
Example 2:
Input: nums = [1,4,6,8,10]
Output: [24,15,13,15,21] */
// ------------------------ SOLUTION -------------------------- //
// Setting left and right to 0 and sum of all nums
// Looping through nums
// Counting how many numbers are on the left and right side of current number
// Pushing the difference between left and right to ans
// Adding current number to left and subtracting it from right
// Time complexity: O(n)
// Space complexity: O(n)
const getSumAbsoluteDifferences = (nums: number[]): number[] => {
let left = 0;
let right = nums.reduce((x, y) => x + y, 0);
const ans: number[] = [];
for (let i = 0; i < nums.length; i++) {
const n = nums[i];
const countLeft = i;
const countRight = nums.length - i;
ans.push(countLeft * n - left - (countRight * n - right));
left += n;
right -= n;
}
return ans;
};
// --------------------------- LOGS --------------------------- //
console.log(getSumAbsoluteDifferences([2,3,5]))
console.log(getSumAbsoluteDifferences([1,4,6,8,10]))
console.log(getSumAbsoluteDifferences([1,2,3,4,5,6,7,8,9,10]))
// ----------------------- CLI COMMAND ------------------------ //
//run ts-node 1685-sumOfAbsoluteDifferences.ts