Day10 - List in python(part-2).ipynb

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   "source": [
    "# **List in Python (Part-2)**"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Operations on Lists:\n",
    "There are three types of Opeartion in List:\n",
    "1. Arithmatic\n",
    "2. Membership\n",
    "3. Loop"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 2, 3, 4, 5, 9, 8, 7, 6, 5]\n",
      "[1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5]\n",
      "[9, 8, 7, 6, 5, 9, 8, 7, 6, 5, 9, 8, 7, 6, 5, 9, 8, 7, 6, 5]\n"
     ]
    }
   ],
   "source": [
    "# Arithmatic opeartion (+, *)\n",
    "\n",
    "L1 = [1,2,3,4,5]\n",
    "L2 = [9,8,7,6,5]\n",
    "\n",
    "# concatenation/Merge\n",
    "print(L1 + L2)\n",
    "\n",
    "\n",
    "print(L1*3)\n",
    "print(L2*4)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "False\n",
      "True\n"
     ]
    }
   ],
   "source": [
    "# membership\n",
    "L1 = [1,2,3,4,5]\n",
    "L2 = [1,2,3,4,[5,6]]\n",
    "\n",
    "print(5 not in L1)\n",
    "print([5,6] in L2)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 9,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "1\n",
      "2\n",
      "3\n",
      "4\n",
      "[5, 6]\n"
     ]
    }
   ],
   "source": [
    "# loops\n",
    "L1 = [1,2,3,4,5]\n",
    "L2 = [1,2,3,4,[5,6]]\n",
    "L3 = [[[1,2],[3,4]],[[5,6],[7,8]]]\n",
    "\n",
    "for i in L2:\n",
    "    print(i)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## List Functions"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 11,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "5\n",
      "7\n",
      "0\n",
      "[0, 1, 2, 5, 7]\n"
     ]
    }
   ],
   "source": [
    "# len/min/max/sorted\n",
    "L = [2,1,5,7,0]\n",
    "\n",
    "print(len(L))\n",
    "print(max(L))\n",
    "print(min(L))\n",
    "print(sorted(L))"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 14,
   "metadata": {},
   "outputs": [
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       "1"
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     "execution_count": 14,
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   ],
   "source": [
    "# count\n",
    "l = [1,2,3,456,67867]\n",
    "\n",
    "l.count(456)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 15,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "1"
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     "execution_count": 15,
     "metadata": {},
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   ],
   "source": [
    "# index\n",
    "l = [3,5,7,9,3,23]\n",
    "\n",
    "l.index(5)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 17,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[78, 6, 4, 3, 2, 1]\n"
     ]
    }
   ],
   "source": [
    "# reverse\n",
    "l = [1,2,3,4,6,78]\n",
    "\n",
    "l.reverse()\n",
    "print(l)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 19,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[2, 1, 5, 7, 0]\n",
      "[0, 1, 2, 5, 7]\n",
      "[2, 1, 5, 7, 0]\n",
      "[0, 1, 2, 5, 7]\n"
     ]
    }
   ],
   "source": [
    "# sort vs sorted\n",
    "L = [2,1,5,7,0]\n",
    "print(L)\n",
    "\n",
    "print(sorted(L))\n",
    "\n",
    "print(L)\n",
    "\n",
    "L.sort()\n",
    "\n",
    "print(L)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "If you want to sort a list in-place, you should use the sort method. If you want to create a new sorted list without modifying the original list, you should use the sorted function"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## **List Comprehension**"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "List Comprehension provides a concise way of creating lists.\n",
    "\n",
    "### newlist = [expression **for** item **in** iterable **if** condition == **True**]\n",
    "\n",
    "\n",
    "Advantages of List Comprehension\n",
    "- More time-efficient and space-efficient than loops.\n",
    "- Require fewer lines of code.\n",
    "- Transforms iterative statement into a formula."
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]\n"
     ]
    }
   ],
   "source": [
    "# Add 1 to 10 numbers to the list\n",
    "\n",
    "# if we use for loop\n",
    "L=[]\n",
    "for i in range(1,11):\n",
    "    L.append(i)\n",
    "    \n",
    "print(L)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]\n"
     ]
    }
   ],
   "source": [
    "# By List Comprehension\n",
    "L = [i for i in range(1,11)]\n",
    "print(L)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 5,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[-6, -9, -12]\n"
     ]
    }
   ],
   "source": [
    "# Scaler multiplication on vecrtor\n",
    "c = [2,3,4]\n",
    "v = -3\n",
    "\n",
    "L = [v*i for i in c]\n",
    "print(L)"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "[4, 9, 16, 25, 36]"
      ]
     },
     "execution_count": 6,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "# Add sqaures \n",
    "L = [2,3,4,5,6]\n",
    "\n",
    "[i**2 for i in L]"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {},
   "outputs": [
    {
     "data": {
      "text/plain": [
       "[5, 10, 15, 20, 25, 30, 35, 40, 45, 50]"
      ]
     },
     "execution_count": 7,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "# Print all numbers divisible by 5 in the range of 1 to 50\n",
    "\n",
    "[i for i in range(1,51) if i%5 == 0]"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Disadvantages of Python Lists\n",
    "\n",
    "- Slow\n",
    "- Risky usage\n",
    "- eats up more memory"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 8,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "[1, 2, 3]\n",
      "[1, 2, 3]\n",
      "[1, 2, 3, 4]\n",
      "[1, 2, 3]\n"
     ]
    }
   ],
   "source": [
    "a = [1,2,3]\n",
    "b = a.copy()\n",
    "\n",
    "print(a)\n",
    "print(b)\n",
    "\n",
    "a.append(4)\n",
    "print(a)\n",
    "print(b)\n",
    "\n",
    "# lists are mutable"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
  }
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